I was thinking it's time to do one of those things again.

Didn't have time to think at fancy rules, so each participant will pick a 3 figures number (between 101 and 949). I'll pick the first three numbers that are drawn at the Joker Lottery on the 26th (the results can be seen here) as the winning comination. The one that picks closest to them wins. If there are more with the same number, the first one wins. The contest ends on the 25th February, midnight (local hour).
The winner will get a C102 Adventura.
Good luck!
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